[tex]\begin{gathered} \text{angles 8p-20 and 10p-60 are the same because they are vertical opposite angles, i.e.,} \\ 8p-20=10p-60,\text{ hence,} \\ 60-20=10p-8p \\ 40=2p \\ p=\frac{40}{2} \\ p=20 \\ \text{with the value of p we can substitute this value in either angles.} \\ EZH=10(20)-60=200-60 \\ =140 \end{gathered}[/tex]
