What is the length of AB if ∅=18° and BC=41? round to the nearest hundredth

First,
Name each side of the triangle
side facing right angle is the hypotanuse
side facing given angle is the opposite
the last side is the adjacent
Opposite = 41
Hypotanuse = AB
[tex]\theta\text{ = 18}[/tex][tex]\begin{gathered} \sin \theta\text{ = }\frac{opposite}{\text{hypotanuse}} \\ \sin 18\text{ = }\frac{41}{AB} \\ 0.309\text{ = }\frac{41}{AB} \\ \text{Cross multiply} \\ 0.309AB\text{ = 41} \\ \text{Divide through by 0.309} \\ AB\text{ = }\frac{41}{0.309} \\ AB\text{ = 132.68} \end{gathered}[/tex]