Question

If t=5pi/3, find the terminal point P(x,y) on the unit circle.

Answer 1

Answer:

$(\frac{1}{2},-\frac{\sqrt[]{3}}{2})$

Explanation:

The given angle:

$\frac{5\pi}{3}=\frac{5\times180}{3}=300^0$

For an angle in standard position on the unit circle, the location of the terminal point will be:

$\begin{gathered} (x,y)=(\cos 300^0,\sin 300^0) \\ =(\frac{1}{2},-\frac{\sqrt[]{3}}{2}) \end{gathered}$