Question

A bag contains 1 red, 1 yellow, 1 blue, and 1 green marble. What is the probability of choosing a green marble, notreplacing it, and then choosing a red marble?161201/2Mark this and returnSave and ExitNextSubmit

Answer 1

SOLUTION

Total outcome is 1 red, 1 yellow, 1 blue, and 1 green = 4 marbles

Probability of picking green marble is

$Pr(green)=\frac{1}{4}$

When the green marble is not replaced, we have the total outcome as 3 marbles remaining

Probability of picking red becoms

$Pr(red)=\frac{1}{3}$

Probability of picking green not replacing and red becomes

$\begin{gathered} Pr(green\text{ and red\rparen = }\frac{1}{4}\times\frac{1}{3} \\ =\frac{1}{12} \end{gathered}$

Hence the answer is

$\frac{1}{12}$