Solution
The given temperature T(d) is given as
[tex]T(d)=\frac{9}{5}d+32[/tex]The temperature C(v) is given as:
[tex]C(v)=v-273[/tex]The temperature F(V) is defined as:
[tex]F(v)=\frac{9}{5}(v-243)+32[/tex]This is simplified to give
[tex]F(v)=\quad\frac{9v}{5}-\frac{2027}{5}[/tex]