(0,10), (1,8), (2,6), (3,4), (5,2), (6,-2)
Explanation
[tex]4x+2y=20[/tex]
Step 1
subtract 4x in both sides
[tex]\begin{gathered} 4x+2y=20 \\ 4x+2y-4x=20-4x \\ 2y=20-4x \end{gathered}[/tex]
Step 2
divide each side by 2
[tex]\begin{gathered} \frac{2y}{2}=\frac{20}{2}-\frac{4x}{2} \\ y=\text{ 10-2x Equation(1)} \end{gathered}[/tex]
Step 3
replace the value of x in equation (1) starting with 0 (table)
[tex]\begin{gathered} \text{when x=0} \\ y=10-2x=10-2(0)=10-0=10 \\ \text{then, when x= 0, y=}10 \end{gathered}[/tex]
point(0,10)
[tex]\begin{gathered} \text{when x= 1} \\ y=10-2x=10-2(1)=10-2=8 \\ (1,8) \end{gathered}[/tex]
point(1,8)
[tex]\begin{gathered} f(1)=10-2(1)=10-2=8 \\ f(2)=10-2(2)=10-4=6 \\ f(3)=10-2(3)=10-6=4 \\ f(4)=10-2(4)=10-8=2 \\ f(5)=10-2(5)=10-10=0 \\ f(6)=10-2(6)=10-12=-2 \end{gathered}[/tex]
I hope this helps you