Question

Convert to standard form: 0=1(x+2) * ((x-(3/5))

Answer 1

Given the equation;

$0=1(x+2)(x-\frac{3}{5})$

First, we multiply the factors, we have;

$\begin{gathered} 0=(x+2)(x-\frac{3}{5}) \\ 0=x(x-\frac{3}{5})+2(x-\frac{3}{5}) \\ 0=x^2-\frac{3}{5}x+2x-\frac{6}{5} \end{gathered}$

Then, multiply each term of the equation by 5, we have;

$\begin{gathered} 5(0)=5x^2-5(\frac{3}{5})x+5(2x)-5(\frac{6}{5}) \\ 0=5x^2-3x+10x-6 \\ 0=5x^2+7x-6 \\ 5x^2+7x-6=0 \end{gathered}$