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Answer:
The dimension of the rectangle is;
[tex]\begin{gathered} \text{length }l=12\text{ inches} \\ \text{width }w=6\text{ inches} \end{gathered}[/tex]Explanation:
1.
Given that the perimeter of the rectangle is 36 inches;
let l and w represent the length and width of the rectangle respectively;
[tex]2(l+w)=36\text{ ------1}[/tex]And its length is two times its width;
[tex]l=2w\text{ ----2}[/tex]substitute equation 2 into 1;
[tex]\begin{gathered} 2(l+w)=36 \\ 2(2w+w)=36 \\ 2(3w)=36 \\ 6w=36 \\ w=\frac{36}{6} \\ w=6\text{ inches} \end{gathered}[/tex]substituting the value of width w into equation 2;
[tex]\begin{gathered} l=2w=2(6) \\ l=12\text{ inches} \end{gathered}[/tex]Therefore, the dimension of the rectangle is;
[tex]\begin{gathered} \text{length }l=12\text{ inches} \\ \text{width }w=6\text{ inches} \end{gathered}[/tex]