Question

use elimination to solve each system of equations 2x -y=47x+3y=27

Answer 1

System of equation

$\begin{gathered} 2x-y=4 \\ 7x+3y=27 \end{gathered}$

Let's multiply equation 1 by 3

$\begin{gathered} 6x-3y=12 \\ 7x+3y=27 \\ \\ 6x+7x-3y+3y=12+27 \\ 13x=39 \\ x=\frac{39}{13} \\ x=3 \end{gathered}$

Now for y

$\begin{gathered} y=2x-4 \\ y=2(3)-4 \\ y=6-4 \\ y=2 \end{gathered}$

The answer would be x = 3 and y = 2