Question

Jake is putting up a new show

Answer 1

Given:

$\begin{gathered} \text{lenght of each piece of wood = 3}\frac{1}{5}\text{ = 3.2 m} \\ Number\text{ of pieces of the same length = 8} \end{gathered}$

First question: An equation that shows how to find the total length

$\text{Total length = length of each piece of wood }\times\text{ number of pieces}$

By substituting the given dimensions to find the actual measurement:

$\begin{gathered} \text{Total length = (3.2 }\times\text{ 8) meters} \\ =\text{ 25.6 meters} \end{gathered}$$\text{Jack measures the total length as 24}\frac{1}{5}\text{ meters or 24.2 m}$

Is he correct?

The answer is NO

Why?

This is because Jack's measurement is not the same as the actual measurement

Given:

$\begin{gathered} 1\text{ box of nails has a mass of 2}\frac{3}{4}\text{ kg or 2.75kg} \\ He\text{ used betw}een\text{ }\frac{1}{2}\text{ to }\frac{3}{4}\text{ of the nails} \end{gathered}$

We are to find the kg of nails he used

Let us represent the total number of nails in the box as T

$It\text{ implies that Jack used betw}een\text{ }\frac{1}{2}T\text{ to }\frac{3}{4}T\text{ nails}$

To obtain the kg of nails he used, we used the analogy:

$\begin{gathered} \text{If T nails weigh 2.75kg, } \\ \text{then }\frac{1}{2}T\text{ nails would weigh 1.375kg and } \\ \frac{3}{4}T\text{ nails would weigh 2.0625kg} \end{gathered}$

Hence, the kg of nails Jack used is :

$\text{between 1.375 to 2.0625kg}$