if the ball lands at the same level from which he was kicked what amount of time was it in the air

Given that the speed of the ball is v = 15.6 m/s
The angle is between the ground and the ball is 60 degrees.
The acceleration due to gravity on the moon is g = 1.62 m/s^2
We have to find the time.
The formula to calculate time is
[tex]t=\frac{2v\sin \theta}{g}[/tex]Substituting the values, the time will be
[tex]\begin{gathered} t=\frac{2\times15.6\times\sin 60^{\circ}}{1.62} \\ =16.68\text{ seconds} \end{gathered}[/tex]Thus, the time taken is 16.68 seconds.