Question

triangle PQR with vertices p(6,-6) and R(9,-7) and R(7,-4) is drawn inside a rectangle as as shown below what's is the area in square units of triangle PQR

Answer 1

Answer:

3.5 square units

Explanation:

We can model the situation as:

Now, the area of the triangle is equal to the area of the square less the areas A, B, and C.

So, the area of the square is equal to:

Area Square = Side x Side = 3 x 3 = 9

On the other hand, the area of the triangles A, B, and C are:

$\begin{gathered} \text{Area A = }\frac{Base\times Height}{2}=\frac{2\times3}{2}=3 \\ \text{Area B=}\frac{Base\times Height}{2}=\frac{1\times2}{2}=1 \\ \text{Area C = }\frac{Base\times Height}{2}=\frac{3\times1}{2}=1.5 \end{gathered}$

Therefore, the area of the triangle with vertices P, Q, and R is:

Area = Area Square - ( Area A + Area B + Area C)

Area = 9 - ( 3 + 1 + 1.5)

Area = 9 - 5.5

Area = 3.5

So, the answer is 3.5 square units