Question

an = 47 +(n-1).3 what is the fourth term of this equation

Answer 1

Given:

$a_n=47+\mleft(n-1\mright)(3)$

To find the fourth term:

Put n=4

We get,

$\begin{gathered} a_4=47+(4-1)(3) \\ =47+(3)(3) \\ =47+9 \\ =56 \end{gathered}$

Therefore, the fourth term of the given equation is 56.