Respuesta :

Given:

[tex]\begin{gathered} F=\text{ 20N} \\ m=10\operatorname{kg} \\ a=\text{?} \end{gathered}[/tex]

We have from Newton's second law of motion:

[tex]F=ma[/tex]

Substitute the values,

[tex]\begin{gathered} 20=10\times a \\ a=\frac{20}{10} \\ a=2\text{ } \end{gathered}[/tex]

Hence the acceleration of the box is 2 m/s^2, that is

[tex]=2ms^{-2}[/tex]

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