Respuesta :

Given:

[tex]\begin{gathered} cos\text{ }\theta=\frac{3}{5} \\ sin\text{ }\theta<0 \end{gathered}[/tex]

We will find the following:

A) the quadrant of the angle.

the cosine of the angle is positive in two quadrants the first and the fourth

In the first quadrant, the sine is (+v)

while in the fourth quadrant the sine is (-v)

So, for the given angle, the angle lying in Q4

B) other five trig function values.

The hypotenuse = h = 5

the adjacent = x = 3

The opposite = y = ±√(5^2 - 3^2)= ±√16 = -4

Choose the (-ve) value because the angle lying in Q4

So, the trig functions will be as follows:

[tex]\begin{gathered} sin\text{ }\theta=\frac{opposite}{hypotenuse}=-\frac{4}{5} \\ \\ tan\text{ }\theta=\frac{opposite}{adjacent}=\frac{-4}{3} \\ \\ sec\text{ }\theta=\frac{1}{cos\text{ }\theta}=\frac{5}{3} \\ \\ cosec\text{ }\theta=\frac{1}{sin\text{ }\theta}=\frac{5}{-4} \\ \\ cot\text{ }\theta=\frac{1}{tan\text{ }\theta}=\frac{3}{-4} \end{gathered}[/tex]

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