Given:
[tex]\begin{gathered} cos\text{ }\theta=\frac{3}{5} \\ sin\text{ }\theta<0 \end{gathered}[/tex]We will find the following:
A) the quadrant of the angle.
the cosine of the angle is positive in two quadrants the first and the fourth
In the first quadrant, the sine is (+v)
while in the fourth quadrant the sine is (-v)
So, for the given angle, the angle lying in Q4
B) other five trig function values.
The hypotenuse = h = 5
the adjacent = x = 3
The opposite = y = ±√(5^2 - 3^2)= ±√16 = -4
Choose the (-ve) value because the angle lying in Q4
So, the trig functions will be as follows:
[tex]\begin{gathered} sin\text{ }\theta=\frac{opposite}{hypotenuse}=-\frac{4}{5} \\ \\ tan\text{ }\theta=\frac{opposite}{adjacent}=\frac{-4}{3} \\ \\ sec\text{ }\theta=\frac{1}{cos\text{ }\theta}=\frac{5}{3} \\ \\ cosec\text{ }\theta=\frac{1}{sin\text{ }\theta}=\frac{5}{-4} \\ \\ cot\text{ }\theta=\frac{1}{tan\text{ }\theta}=\frac{3}{-4} \end{gathered}[/tex]