Question

Object A, which has been charged to +11.62 nC, is at the origin. Object B, which has been charged to -20.04 nC, is at x=0 and y=1.96 cm. What is the magnitude of the electric force, in micro-Newtons, on object A?

Answer 1

Given

Charge on object A, q=11.62 nC at x=0

Charge on object B, q'=-20.04 nC at x=0, y=1.96 cm

To find

The electric force

Explanation

The electric force is given by

$\begin{gathered} F=\frac{kqq^{\prime}}{r^2} \\ \Rightarrow F=9\times10^9\frac{11.62\times10^{-9}\times20.04\times10^{-9}}{(1.96\times10^{-2})^2} \\ \Rightarrow F=5455.49\text{ microN} \end{gathered}$

Conclusion

The electric force is 5455.49 micro-N