Answer:
0.1 N
Explanation:
The magnitude of a force exerted by two charges q1 and q2 that are separated by a distance of r is calculated as
[tex]F=k\frac{q_1q_2}{r^2}[/tex]So, replacing k = 9 x 10^9 N m²/C², r = 0.30 m, and q1 and q2 by 1.0 x 10^-6 C, we get
[tex]\begin{gathered} F=(9\times10^9Nm^2/C^2)\frac{(1\times10^{-6}C)(1\times10^{-6}C)}{(0.30m)^2} \\ F=0.1N \end{gathered}[/tex]Therefore, the repulsive force has a magnitude of 0.1 N
