Question

assume that females have pulse rates that are normally distributed with a mean of 74.0 beats per minute and a standard deviation of 12.5 beats per minute.if 1 adult female is randomly selected find the probability that her pulse rate is less than 81 beats per minute.

Answer 1

SOLUTION:

$Z\text{ score = }\frac{\text{ Raw score - Mean Score}}{\text{Standard Deviation}}$$\begin{gathered} Z\text{ score = }\frac{81\text{ - 74}}{12.5} \\ \\ Z\text{ score = }\frac{7}{12.5} \\ \\ Z\text{ score = 0.56} \end{gathered}$

From the Z-score probability table;

P < 81 = 0.7123

CONCLUSION:

If one adult female is randomly selected, the probability that her pulse rate is less than 81 beats per minute is 0.7123