Sketch the graph of the function. identify the vertex and axis of symmetry. Y=-1/6x²+5

The function is:
[tex]y=-\frac{1}{6}x^2+5[/tex]Now we can derivate to find the vertex so:
[tex]\begin{gathered} -\frac{2}{6}x=0 \\ x=-3 \end{gathered}[/tex]so the veryex is in -3
now we can operate in -2 and -1 so:
[tex]\begin{gathered} y=-\frac{1}{6}(-2)+5 \\ y=\frac{1}{3}+5 \\ y=5.33 \end{gathered}[/tex]for -1:
[tex]\begin{gathered} y=-\frac{1}{6}(-1)+5 \\ y=5.16 \end{gathered}[/tex]so the graph is: