What is the ratio of the areas (large to small quadrilaterals) of these two figures?

Answer:
36 : 1
Explanation:
Consider the ratio of the side lengths of the quadrilaterals:
[tex]\frac{42}{7}=\frac{36}{6}=6[/tex]This means that the two given quadrilaterals are similar.
For any two similar figures, the ratio of their areas is the squares of the ratio of their side lengths.
Therefore:
[tex]\frac{\text{ Area of Larger Figure}}{\text{ Area of Smaller Figure}}=(\frac{42}{7})^2=\frac{42^2}{7^2}=\frac{36}{1}[/tex]The ratio of the areas (large to small quadrilaterals) is 36:1.