Given the selling prices for homes in a certain community are approximately normally distributed
Mean = μ = $321,000
Standard deviation = σ = $38,000
For the following cases, we will find the z-score as follows:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
And we will use the following chart:
Estimate the percentage of homes in this community with selling prices:
A) between $245,000 and $397,000
So, the z-score for the given prices will be:
[tex]\begin{gathered} $245,000$\rightarrow z=\frac{245000-321000}{38000}=-2 \\ 397,000\rightarrow z=\frac{397000-321000}{38000}=2 \end{gathered}[/tex]
So, the percentage when -2 < z < 2 will be as shown from the chart = 95%
B) above $435,000
[tex]435,000\rightarrow z=\frac{435000-321000}{38000}=3[/tex]
The area under the curve = 100%
So, the percentage when z > 3 will be = 0.5%
C) below $283,000
[tex]283,000\rightarrow z=\frac{283000-321000}{38000}=-1[/tex]
so, the percentage when z < -1 will be = 50 - 34 = 16%
D) between $283,000 and $435,000
We will find the percentage in case if: -1 < z < 3
So, the percentage will be = 34 + 34 + 13.5 + 2 = 83.5%