Answer
[tex]y=-\frac{5}{6}x+3[/tex]Explanation
The given line equation is
[tex]y=\frac{6}{5}x+1[/tex]For two equations that are perpendicular with slopes m₁ and m₂,
m₁ m₂ = -1
From all the options given, only equation y = -5/6(x) + 3 will be perpendicular to the given line equation.
m₁ = 6/5 and m₂ = -5/6
Hence,
[tex]\begin{gathered} \frac{6}{5}\times-\frac{5}{6}=-1 \\ \text{This satisfies m}_1m_2=-1 \end{gathered}[/tex]