The vertex of this parabola is at (-2, 1). Which of the following could be itsequation?5(-2,1)A. x = 4(y- 1)2-2B. y = 4(x - 2)2 + 1c. y = 4(x - 2)2-1D. x = 4(y + 1)2-2

The vertex of this parabola is at 2 1 Which of the following could be itsequation521A x 4y 122B y 4x 22 1c y 4x 221D x 4y 122 class=

Respuesta :

A parabola can be written in the vertex form as follows:

[tex]y=a(x-h)^2+k[/tex]

Where:

[tex](h,k)[/tex]

Are the coordinates of the vertex.

Since the vertex is at:

[tex]\begin{gathered} (h,k)=(-2,1) \\ \end{gathered}[/tex]

The equation is:

[tex]\begin{gathered} y=a(x-(-2))^2+1 \\ y=a(x+2)+1 \end{gathered}[/tex]

But, since it is a horizontal parabola:

[tex]\begin{gathered} x=a(y-k)+h \\ so\colon \\ x=a(y-1)^2-2 \end{gathered}[/tex]

Therefore, the only valid option is:

[tex]x=4(y-1)^2-2[/tex]

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