Answer
2.95 x 102₃
Procedure
1. The first step is to search for the formula of lithium carbonate or deduct it using nomenclature rules,
-The formula is Li₂CO₃
2. Then determine the molecular weight of the molecule
-The molecular weight is 73.891 g/mol
3. Convert from grams to moles and from moles to molecules
[tex]36.2\text{ g Li}_2\text{CO}_3\frac{1\text{ mol}}{73.891\text{ g}}\frac{6.022\times10^{23}}{1\text{ mole}}=2.95\times10^{23\text{ }}molecules[/tex]
