Question

In the lab, Charlie has two solutions that contain alcohol and is mixing them with each other. He uses 3 times as much Solution A as Solution B. Solution A is15% alcohol and Solution B is 10% alcohol. How many milliliters of Solution B does he use, if the resulting mixture has 330 milliliters of pure alcohol?Number of millilitersSolution B :

Answer 1

SOLUTION:

Step 1:

In this question, we are told that Charlie uses 3 times as much

Solution A as Solution B.

A = y

B = 3 y

Now, Solution A is 15% alcohol and Solution B is 10% alcohol and the resulting mixture has 330 milliliters of pure alcohol.

Step 2:

We have that:

$\begin{gathered} y\text{ x 15 \% + 3 y x 10 \% = 330 x 100\%} \\ 0.15\text{ y }+\text{ 0. 3 y = 330} \\ 0.\text{ 45 y = 330} \\ \text{Divide both sides by 0. 45, we have that:} \\ \text{y = }\frac{330}{0.45} \\ \text{y = 733.333} \end{gathered}$

Step 3:

Since the volume of solution B = 3y

$\begin{gathered} \text{Then , the volume = 3 y = 3 x 733.333} \\ \approx\text{2200} \end{gathered}$

CONCLUSION:

The volume of solution B = 2200 millimetres