Question

What are the potential solutions of In(x2 - 25) = 0?ООX=1-13x=+5x=126OX= +10

Answer 1

solution

$\begin{gathered} ln\mleft(x^2\: -\: 25\mright)\: =\: 0 \\ x^2-25=1 \\ x^2-25+25=1+25 \\ x^2=26 \\ x1=\sqrt[]{26} \\ x2=-\sqrt[]{26} \end{gathered}$

answer:

$x=\pm\sqrt[]{26}$