Given: The rational fraction below
[tex]f(x)=\frac{x+1}{x-3},for,x\ne3[/tex]
To Determine: The domain of the function
Solution
[tex]\begin{gathered} The\:domain\:of\:a\:function\:is\:the\:set\:of\:input\:or\:argument\:values \\ \:for\:which\:the\:function\:is\:real\:and\:defined \end{gathered}[/tex]
The function is undefined when x is equal to 3.
Hence, the domain of the function would be x less than 3 and x greater than 3.
Let us represents the domain in interval notation
[tex]\begin{gathered} Domain:x<3,x>3 \\ Interval-notation \\ (-\infty,3)\cup(3,\infty) \end{gathered}[/tex]
Hence, the domain is (-∞,3) U (3, ∞)