Answer:
The concentration of HCl is 0.0467 M.
Explanation:
What is given?
Volume 1 (V1) = 0.621 L,
Concentration 1 (C1) = 0.7 M,
Volume 2 (V2) = 9.3 L.
What do we need? Concentration 2 (C2).
Step-by-step solution:
To solve this problem we have to use the following formula:
[tex]C_1V_1=C_2V_2.[/tex]Where in this case, concentration and volume 1 correspond to NaOH, and concentration and volume 2 correspond to HCl.
We want to find the concentration of HCl so we have to solve for 'C2' and replace the given data in the formula, like this:
[tex]\begin{gathered} C_2=\frac{C_1V_1}{V_2}, \\ \\ C_2=\frac{0.7\text{ M}\cdot0.621\text{ L}}{9.3\text{ L}}, \\ \\ C_2=0.0467\text{ M.} \end{gathered}[/tex]The answer would be that the concentration of HCl is 0.0467 M.
