We will have the following:
First, we transform the revolutions per second to radians, that is:
[tex]\begin{cases}-420rev/\min =-840\pi/\min =-14\pi/s \\ \\ 610\text{rev}/\min =1220\pi/\min =\frac{61\pi}{3}/s\end{cases}[/tex]Now, we will have that the final angular velocit will be given by:
[tex]-14\pi/s+\frac{6\pi}{3}/s=-12\pi/s[/tex]So, the angular speed after coupling is -12pi/s. [That is the total angular speed will be counterclock wise]