The length of time a person takes to decide which shoes to purchase is normally distributed with a mean of 8.21 minutes and a standard deviation of 1.90. Find the probability that a randomly selected individual will take less than 5 minutes to select a shoe purchase. Is this outcome unusual?Probability is 0.045, which is usual as it is not less than 5%Probability is 0.954, which is unusual as it is greater than 5%Probability is 0.954, which is usual as it is greater than 5%Probability is 0.045, which is unusual as it is less than 5%

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Given:

[tex]\begin{gathered} mean(\mu)=8.21 \\ standard-deviation(\sigma)=1.90 \end{gathered}[/tex]

To Determine: The probability that a randomly selected individual will take less than 5 minutes to select a shoe purchase

Solution

P(x<5)

The z score formula is given as

[tex]z=\frac{x-\mu}{\sigma}[/tex]

Substitute the given into the formula

[tex]z=\frac{5-8.21}{1.90}[/tex][tex]\begin{gathered} z=-\frac{3.21}{1.9} \\ z=-1.68947 \end{gathered}[/tex]

The probabilty would be

[tex]\begin{gathered} P(x<-1.68947)=0.04556 \\ \approx0.045 \\ \approx4.5\% \end{gathered}[/tex]

Hence, the probability is 0.045, which is unusual as it is less than 5%

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