First we will calculate the volume of the cone with the following equation.
[tex]\begin{gathered} V=\frac{1}{3}\pi\cdot r^2\cdot h \\ \\ V=\frac{1}{3}\cdot3.14\cdot6^2\cdot13 \\ \\ V=\frac{1}{3}\cdot3.14\cdot36\cdot13 \\ V=489.8\text{ mm3} \end{gathered}[/tex]The answer would be 489.8 mm3
