Question

find a solution to the equation. x^2-6x+8=0

Answer 1

The equation is given as,

$x^2-6x+8=0$

Factorizing the given equation,

$\begin{gathered} x^2-6x+8=0 \\ x^2-4x-2x+8=0 \\ \end{gathered}$

Taking common terms out of the bracket,

$\begin{gathered} x\left(x-4\right)-2\left(x-4\right)=0 \\ (x-4)(x-2)=0 \end{gathered}$

Therefore the value of x is calculated as,

$\begin{gathered} x-4=0\text{ and x-2 = 0} \\ x\text{ = 4 and x = 2} \end{gathered}$

Thus the solution of the given equations are 2 and 4.