special right triangles find the values of the variables answers must be in simplest form

For right triangles we can use trigonmoetrical ratios if we want calculate the oppisite side of an angle
on this case we use sine to calculate m
[tex]\sin (\alpha)=\frac{O}{H}[/tex]where alpha is the angle, O the opposite side of the angle and H the hypotenuse of the triangle
on this triangle
alpha is 45°
the front side is m
and the hypoteuse 7
so replacing
[tex]\sin (45)=\frac{m}{7}[/tex]on this point we can solve m form the equation and calulate
[tex]\begin{gathered} m=7\sin (45) \\ m=\frac{7\sqrt[]{2}}{2} \\ \\ m\approx4.95 \end{gathered}[/tex]