Question

Given two consecutive integers. The sum of seven times the first integer and three times the second integer is 93. Find the integers.

Answer 1

Let X be the first integer.

Then, the second integer is X+1.

The sum of 7 times the first integer (7*X) and 3 times the second integer (3*(X+1)) is 93.

We can write this as:

$\begin{gathered} 7X+3(X+1)=93 \\ 7X+3X+3=93 \\ 10X=93-3 \\ 10X=90 \\ X=\frac{90}{10} \\ X=9 \end{gathered}$

The first integer is 9 and the second integer is 10.