Find the angle of θ of the camera lens, given the measurements shown in the figure.(Round to the nearest tenth)

Solution
The diagram below will be of help
From the red triangle in the image above, we have the opposites and the adjacent sides of the triangle
From the concept of SOHCAHTOA
[tex]\begin{gathered} tan(\frac{\theta}{2})=\frac{opposite}{adjacent} \\ tan(\frac{\theta}{2})=\frac{21.8}{374} \\ \frac{\theta}{2}=tan^{-1}(\frac{21.8}{374}) \\ \frac{\theta}{2}=3.335925908 \\ \theta=6.671851816 \\ \theta=6.7^{\circ}\text{ \lparen to the nearest tenth\rparen} \end{gathered}[/tex]Therefore, the answer is
[tex]\theta=6.7^{\operatorname{\circ}}\operatorname{\lparen}\text{to the nearest tenth}\operatorname{\rparen}[/tex]