Question

Leo had $91, which is 7 times as much money as Alison had. How muchmoney did Alison have?Select the correct solution method below, where x represents Alison's money.A. 7x = 91. Divide both sides by 7. Alison had $13.B. X- 7 = 91. Add 7 to both sides. Alison had $98.C. = 91. Multiply both sides by 7. Alison had $637.D. x+ 7 = 91. Subtract 7 from both sides. Alison had $846OLDNAT

Answer 1

Given:

Leo had $91, which is 7 times as much money as Alison had.

Let x represents Alison's money.

So, the expression for Leo's money is,

$7x=91$

Divide both sides of the above equation by 7.

$\begin{gathered} \frac{7x}{7}=\frac{91}{7} \\ x=13 \end{gathered}$

So, Alison had $13.

Therefore, the correct solution method is

A) 7x = 91. Divide both sides by 7. Alison had $13.