Solve:
[tex]\text{log}_{x+5}(36)=2[/tex]We apply the rule:
[tex]\text{log}_b(a)=y\longrightarrow b^y=a[/tex]So in this case we have:
a = 36, b=x+5, y=2
Then, we can apply the rule as:
[tex]\begin{gathered} \text{log}_{x+5}(36)=2\longrightarrow(x+5)^2=36 \\ (x+5)^2=36 \\ x+5=36^{\frac{1}{2}} \\ x+5=6 \\ x=6-5 \\ x=1 \end{gathered}[/tex]