Answer:
[tex](6x+7)(6x-7)[/tex]Explanation:
Given the below expression;
[tex]36x^2-49^{}[/tex]Since both terms are perfect squares, we can rewrite the above expression as;
[tex](6x)^2-7^2[/tex]We can now apply the below difference of squares formula;
[tex]a^2-b^2=(a+b)(a-b)[/tex]If we compare the above formula with our expression, we can see that a = 6x and b = 7.
Let's go ahead and substitute;
[tex](6x)^2-7^2=(6x+7)(6x-7)[/tex]