Respuesta :

Answer:

[tex](6x+7)(6x-7)[/tex]

Explanation:

Given the below expression;

[tex]36x^2-49^{}[/tex]

Since both terms are perfect squares, we can rewrite the above expression as;

[tex](6x)^2-7^2[/tex]

We can now apply the below difference of squares formula;

[tex]a^2-b^2=(a+b)(a-b)[/tex]

If we compare the above formula with our expression, we can see that a = 6x and b = 7.

Let's go ahead and substitute;

[tex](6x)^2-7^2=(6x+7)(6x-7)[/tex]

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