Given that the force is F = 80 N
The length of the conductor is L = 80 cm = 0.8 m
The magnetic field of flux density is B = 0.5 T
The angle is 30 degrees.
We have to find the current in the circuit.
The current in the circuit will be
[tex]\begin{gathered} F=IBLsin30^{\circ} \\ I=\frac{F}{\text{BLsin}30^{\circ}} \\ =\frac{80}{0.5\times0.8\times0.5} \\ =\text{ 400 A} \end{gathered}[/tex]The current in the circuit will be 400 A
