Answer:
[tex]P\text{ = 0.992 atm}[/tex]Explanation:
Here, we want to get the pressure occupied by the gas under the given conditions
We can use the ideal gas equation here
Mathematically, we have this as:
[tex]PV\text{ = nRT}[/tex]P is the pressure which we want to calculate
V is the volume occupied by the gas given as 42.5 L
n is the number of moles, given as 1.52 moles
R is the molar gas constant which is :
[tex]R\text{ = }0.082057LatmK^{-1}mol^{-1}[/tex]T is the temperature which we have to convert to absolute temperature scale (Kelvin) by adding 273.15 K to the Celsius temperature
[tex]273.15\text{ + 65 = 338.15 K}[/tex]Let us rewrite the equation in terms of the Pressure, which we want to calculate
We have this as:
[tex]P\text{ = }\frac{nRT}{V}[/tex]Finally, we proceed to substitute the values given above:
[tex]\begin{gathered} P\text{ = }\frac{1.52\text{ }\times0.082057\times338.15}{42.5} \\ \\ P\text{ = 0.992 atm} \end{gathered}[/tex]