Given the following question:
[tex]f\mleft(x\mright)=x^3+5x^2-7x-3[/tex][tex]\begin{gathered} f(x)=x^{3}+5x^{2}-7x-3 \\ x^3=3x^2 \\ x^2=2x \\ 5x\times2x=10x \\ x=1 \\ 7x=7\left(1\right)=7\times1=7 \\ 3x^2+10x-7 \\ \text{ To find the critical points} \\ 3x^2+10x-7=0 \\ -\frac{5}{3}+\frac{\sqrt{46}}{3} \\ -\frac{\sqrt{46}}{3}-\frac{5}{3} \\ \text{ The critical points are:} \\ -\frac{5-\sqrt{46}}{3},\frac{484-92\sqrt{46}}{27} \\ -\frac{5+\sqrt{46}}{3},\frac{484+92\sqrt{46}}{27} \\ \end{gathered}[/tex]