Given:
[tex]\cot A=\frac{24}{7}=\frac{adjacent}{opposite}[/tex]so, the opposite to the angle A = 7
The adjacent to the angle A = 24
Using the Pythagorean theorem to find the hypotenuse
[tex]\text{hypotenuse}=\sqrt[]{7^2+24^2}=\sqrt[]{49+576}=\sqrt[]{625}=25[/tex]The angle A is in Quadrant I, so the sin will be positive
[tex]\begin{gathered} \sin A=\frac{opposite}{hypotenuse} \\ \\ \sin A=\frac{7}{25} \end{gathered}[/tex]