So, we want to find the slope of the line that goes through the points (-11 , -13) and (-8,3).
For this, remember that:
Given two points that lie on a line:
[tex]\begin{gathered} (x_1,y_1) \\ (x_2,y_2) \end{gathered}[/tex]The slope of the line that goes through these points can be found if we apply the following formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]In our question, we are given that:
[tex]\begin{gathered} (x_1,y_1)=(-11,-13) \\ (x_2,y_2)=(-8,3) \end{gathered}[/tex]So,
[tex]\begin{gathered} x_1=-11 \\ y_1=-13 \\ x_2=-8 \\ y_2=3 \end{gathered}[/tex]The only thing we have to do now, is to replace. So,
[tex]m=\frac{3-(-13)}{-8-(-11)}=\frac{3+13}{-8+11}=\frac{16}{3}[/tex]Therefore, the slope of the line is 16/3