Respuesta :

So, we want to find the slope of the line that goes through the points (-11 , -13) and (-8,3).

For this, remember that:

Given two points that lie on a line:

[tex]\begin{gathered} (x_1,y_1) \\ (x_2,y_2) \end{gathered}[/tex]

The slope of the line that goes through these points can be found if we apply the following formula:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

In our question, we are given that:

[tex]\begin{gathered} (x_1,y_1)=(-11,-13) \\ (x_2,y_2)=(-8,3) \end{gathered}[/tex]

So,

[tex]\begin{gathered} x_1=-11 \\ y_1=-13 \\ x_2=-8 \\ y_2=3 \end{gathered}[/tex]

The only thing we have to do now, is to replace. So,

[tex]m=\frac{3-(-13)}{-8-(-11)}=\frac{3+13}{-8+11}=\frac{16}{3}[/tex]

Therefore, the slope of the line is 16/3

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