Answer
The freezing point of the solution = 273.748 K
Explanation
Given:
Molality of aqueous AlCl3 solution = 0.10 m
What to find:
The freezing point of the solution
Solution:
The freezing point depression of the solution can be calculated using the ormula below:
ΔT = i x m x Kf
i = Vant Hoff's factor for AlCl3 = 4
m = molality of the solution = 0.10 m
Kf = freezing point constant of water = 1.87 Km⁻¹
ΔT = 4 x 0.10 m x 1.87 Km⁻¹ = 0.748 K
Since the freezing point of water = 273 K
Therefore, the freezing point of the solution = 273 K 0.748 K = 273.748 K
