Solve on the interval [0,27): 2 cscx -3 = -5 ОА. Зл 2 O 2T 4T B. 3.3 7 T 1 IT c O T O D. IS

Answer:
[tex]x\text{ = }\frac{3\pi}{2}[/tex]Explanation:
We want to get the value of x on the interval for which the identity holds true
We have this as follows:
[tex]\begin{gathered} \csc \text{ x = }\frac{1}{\sin \text{ x}} \\ \\ \frac{2}{\sin \text{ x}}\text{ = -5+3} \\ \\ \frac{2}{\sin \text{ x}}\text{ = -2} \\ \\ \sin \text{ x = -1} \\ \\ x\text{ = }\sin ^{-1}\text{ (-1)} \\ \\ x\text{ = }\frac{3\pi}{2} \end{gathered}[/tex]