Question

The chemical formula for cesium chloride CsClA chemist measured the amount of the cesium chloride produced during an experiment. She finds that 9.5 g of cesium chloride is produced. Calculate the number of moles of cesium chloride produced. Be sure your answer has the correct number of significant digits

Answer 1

We know that a chemist finds that 9.5 g of cesium chloride is produced and we must find the number of moles of cesium chloride

In order to find the number of moles we must use the next formula

$\text{ number of moles}=\frac{mass}{molar\text{ mass}}$

In this case, the mass produced is given 9.5 g and the molar mass of the cesium chloride is 168.36 g/mol

Now, we must replace the values in the formula

$\text{ number of moles}=\frac{9.5g}{168.36\frac{g}{mol}}$

Finally, we must simplify the equation

$\text{ number of moles}=0,0564267046804467\text{mol}$

Giving the answer using the correct number of significant digits:

$\text{ number of moles}=5.6\cdot10^{-2}\text{mol}$

ANSWER:

$5.6\cdot10^{-2}$