In order to calculate the discriminant, let's compare the given equation with the standard form of a quadratic equation, then we use the coefficients in the formula for the discriminant:
[tex]\begin{gathered} y=ax^2+bx+c \\ -2x^2+9x-2=0 \\ a=-2,b=9,c=-2 \\ \\ \Delta=b^2-4ac \\ \Delta=9^2-4\cdot(-2)(-2) \\ \Delta=81-16 \\ \Delta=65 \end{gathered}[/tex]
Since the discriminant is greater than 0, that means the quadratic equation has 2 real solutions.
