Respuesta :

Solution

[tex]A=\frac{\sqrt[]{3}\sqrt[4]{125}}{7^3}[/tex]

And we want to find log_2 A and we can do this :

[tex]\log _2A=\frac{1}{2}\log _2(3)+\frac{3}{4}\log _2(5)-3\log _2(7)[/tex]

And the reason is because:

[tex]\log _2(\sqrt[4]{125})=\log _2(\sqrt[4]{25\cdot5})=\log _2(\sqrt[4]{5^3}))=\frac{3}{4}\log _2(5)[/tex]

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