Answer:
Substituting the values of x and y will give;
[tex](x-3)^2+\frac{1}{2}y=7[/tex]
Explanation:
Given the expression;
[tex](x-3)^2+\frac{1}{2}y[/tex]
for values;
[tex]\begin{gathered} x=5 \\ y=6 \end{gathered}[/tex]
substituting the given values;
[tex](x-3)^2+\frac{1}{2}y=(5-3)^2+\frac{1}{2}(6)=2^2+\frac{6}{2}=4+3=7[/tex]
Therefore, substituting the values of x and y will give;
[tex](x-3)^2+\frac{1}{2}y=7[/tex]
