Question

10.A child-sized swimming pool can be modeled by a cylinder. The pool has a diameter of 6 feetand a height of 12 inches. The pool is filled with water to of its height. Determine and statethe volume of the water in the pool, to the nearest cubic footOne cubic foot equals 7.48 gallons of water. Determine and state, to the nearest gallon, the numberof gallons of water in the pool.

Answer 1

The volume of a cylinder is:

$\begin{gathered} V=\pi\times\frac{d^2}{4}\times h \\ d=diameter \\ h=\text{height} \end{gathered}$

The height of the cylinder: 12 inches

Since 1 feet is 12 inches, then we can say the height of the cylinder is 1 foot.

diameter: 6 feet.

Now we can find the volume of the pool (cylinder):

$\begin{gathered} V=\pi\times\frac{6^2}{4}\times1 \\ V=9\pi\approx28.274ft^3 \\ \\ \therefore V=28ft^3\text{ (to the nearest cubic foot)} \end{gathered}$

V = 28 cubic feet

One cubic foot equals 7.48 gallons, therefore to find the amount of water in gallons is:

$\begin{gathered} 7.48\times28.274 \\ =211.489\text{gallons}=212gallons\text{ (to the nearest gallon)} \end{gathered}$